Square 35 8w
Square 35 8w
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I need math help.?
I don't expect them all to be done, but how do you do them?
Factoring Trinomials. -solve each equation
1) 3h^2 +2h-16=0
2)15n^2 - n=2
3) 10g^2 + 10 =29g
4) 18a^2+10a= -11a+4
5) 12x^2 - 1+ -x
Factoring Differences of Squares
1)32-8y^2
2)36z^3-9z
3)45q^3-20q
Solve
1)64p^2 =9
2)98b^2 - 50=0
3)32-162k^2=0
4) 16/49 - v^2 =0
Perfect squares and factoring
1)6x^2+11x-35
2) 50q^2-60q+18
3)w^4-8w^2-9
Thank you, like I said, They don't all need to be done, but atleast one from each set of problems?
From the first set:
1.) 3h^2 +2h-16=0
(3h + 8)(h - 2) = 0
This gives you two equations you have to solve individually. That is, set each factor equal to zero and solve for h.
3h + 8 = 0
3h = -8
h = -8/3
and
h - 2 = 0
h = 2
If you are not confident with you answer, you can always substitute you answer into the original equation to see if you are right. You should get 0 = 0 for both results.
3(-8/3)^2 + 2(-8/3) - 16 = 0
3(64/9) - 16/3 - 16 = 0
0 = 0 (true)
You will get the same thing for h = 2. That is the beauty of solving problems like these -- you will always know if you are right.
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Second set:
1.) 32-8y²
= 8(4 - y²)
= 8(2 - y)(2 + y)
3.) 45q^3-20q
= 5q(9q² - 4)
= 5q(3q - 2)(3q + 2)
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Third set:
4.) 16/49 - v² = 0
First note that 16/49 = (4/7)²
The difference of two squares is factored into
( (4/7)² + v)( (4/7)² - v) = 0
v = 4/7
and
v = -4/7
Check results using original equation....
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Last problem set:
I'll do the third problem since it looks like the trickiest one.
3.) w^4-8w^2-9
Note that you do not have the difference of two squares. Before doing anything, note that you answer will take the form
(w² + )(w² - )
Where I left spaces for what is uknown. Now, what two numbers when multiplied together give you -9 ?
3 and - 3, but these numbers sum to 0.
The only other two numbers are -9 and 1, or 9 and -1. Since the sum of -9 and 1 is -8, these are your numbers. So you have
(w² - 9)(w² + 1)
Now we do have the difference of two squares. The factor on the right becomes
(w - 3)(w + 3)
and the final answer is
(w - 3)(w + 3)(w² + 1)
Sorry I couldn't do more, but problems like these are not easy to type =]